The 20.0 cm by 35.0 cm rectangular circuit shown in the figure (Figure 1) is hin

Question

The 20.0 cm by 35.0 cm rectangular circuit shown in the figure (Figure 1) is hinged along side ab. It carries a clockwise 5.00 A current and is located in a uniform 1.20 T magnetic field oriented perpendicular to two of its sides, as shown

Part A

Which force exerts a torque about the hinge ab?

Part B

Calculate only the force that exert the torque mentioned in part (A).

F= (N)

Part C

Use your results from part (B) to calculate the torque that the magnetic field exerts on the circuit about the hinge axis ab.

? = (N.m)

Explanation / Answer

A) there is no force acting on bc and ad ,since the angle between B and current i is zero.hence Force F = B*i*L*sin(0) = 0 N

but Force on cd is F_cd = B*i*L = 1.2*5*0.2 = 1.2 N

So the F_cd exerts a torque about the hinge ab

B) F_cd = B*i*L = 1.2*5*0.2 = 1.2 N

C) Torque T = r*F = 0.35*1.2 = 0.42 N-m

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