The 20.0 cm by 35.0 cm rectangular circuit shown in the figure (Figure 1) is hin

Question

The 20.0 cm by 35.0 cm rectangular circuit shown in the figure (Figure 1) is hinged along side ab. It carries a clockwise I = 4.50 A current and is located in a uniform 1.50 T magnetic field oriented perpendicular to two of its sides, as shown.The 20.0 cm by 35.0 cm rectangular circuit shown in the figure (Figure 1) is hinged along side ab. It carries a clockwise I = 4.50 A current and is located in a uniform 1.50 T magnetic field oriented perpendicular to two of its sides, as shown.Calculate the forces that exert a torque about the hinge ab mentioned in Part B. Use your results from Part C to calculate the torque that the magnetic field exerts on the circuit about the hinge axis ab.

Explanation / Answer

B = 1.5 T

magnetic force will act only on side cd and ab (other two current are parallel to B)

but torque about ab from these forces will be non zero for the cd edge

so

force on edge cd = F_cd = I * L_cd * B = 4.5 * 0.2 * 1.5 = 1.35 N upword(out of plan)

torque due to this force about ab = F_cd * L_ab = 1.35 * 0.35 = 0.4725 Nm

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