Problem 9.42 One billiard ball is shot east at 1.6 m/s . A second, identical bil

Question

Problem 9.42 One billiard ball is shot east at 1.6 m/s . A second, identical billiard ball is shot west at 0.80 m/s . The balls have a glancing collision, not a head-on collision, deflecting the second ball by 90 degree and sending it north at 1.31 m/s. Part A What is the speed of the first ball after the collision? Express your answer to two significant figures and include the appropriate units. Part B What is the direction of the first ball after the collision? Give the direction as an angle south of east. Express your answer to two significant figures and include the appropriate units.

Explanation / Answer

Let the mass of ball = m
Initial Momentum in X direction = m* 1.6 - m*0.8 = 0.8 m

Final Momentum in X Direction = m* v*cos()

m* v*cos() = 0.8 m
v*cos() = 0.8 --------1

Initial Momentum in y direction = 0

Final Momentum in y Direction = m* 1.31 - m*v*sin()

0 = m* 1.31 - m*v*sin()
v*sin() = 1.31 -------------2

eq 2/ eq1

tan*() = 1.31/0.8
= 58.6o South of East

v*sin(58.6) = 1.31
v = 1.54 m/s


(a) Speed of First Ball after collison, v = 1.54 m/s
(b) Direction , = 58.6o South of East

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