Problem 9.08 The two trees in (Figure 1) are 6.8 m apart. A backpacker is trying
ID: 1444539 • Letter: P
Question
Problem 9.08
The two trees in (Figure 1) are 6.8 m apart. A backpacker is trying to lift his 18-kg backpack out of the reach of bears.
Part A Calculate the magnitude of the force F->that he must exert downward to hold the backpack so that the rope sags at its midpoint by 2.0 m . Express your answer to two significant figures and include the appropriate units.
Part B Calculate the magnitude of the force F-> that he must exert downward to hold the backpack so that the rope sags at its midpoint by 0.20 m . Express your answer to two significant figures and include the appropriate units.
Explanation / Answer
m = 18 kg , d = 6.8 m
weight of backpack = 18*9.8 = 176.4 N
Half weight needs to be supported by each 1/2 rope. w =176.4/2 = 88.2 N
The pack is (6.8/2) = 3.4 m. from each tree.
a) Angle below horizontal with 2m. sag = arctan. (2/3.4), = 30.46 degrees.
The vertical load is 88.2 N., so rope tension needed = 88.2/ (sin 30.46), = 174 N.
T =170 N
b) Angle below horizontal = arctan (0.2/3.4), = 3.37 degrees.
Tension needed = 88.2/ (sin 3.37), = 1502 N.
T =1500 N
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.