Problem 9.107 Part A In a physics lab, a cube slides down a frictionless incline

Question

Problem 9.107 Part A In a physics lab, a cube slides down a frictionless incline as shown in the figure and elastically strikes another cube at the bottom that is only 1/2 its mass. (Figure 1) If the incline is 35 cm high and the table is 95 cm off the floor, where does each cube land? [Hint Both leave the incline moving horizontally.] Enter your answers numerically separated by a comma. Express your answers using two significant figures Submit My Answers Give Up Continue Figure 1 of 1 35 cm 1/n 95 cm

Explanation / Answer

v = sqrt [2 * 9.8 * 0.35] = 2.62 m/s

momentum is conserved and Kinetic energy is conserved

M * 2.62 = M V1 + m V2

0.5 * M * 2.622 = 0.5 M V12 + 0.5 m V22

m = M/2

0.5 * M * 2.622 = 0.5 M V12 + 0.5 (M/2) V22

2.62 = V1 + V2/2

2.622 = V12 + V22/2

V1 = 2.62 / 3 = 0.873 m/s

V2 = 2.62 * 4 / 3 = 3.49 m/s

t = sqrt [2 h / g] = sqrt [2 * 0.95 / 9.8] = 0.440 s

xM = 0.873 * 0.44 = 0.384 m

xm = 3.49 * 0.44 = 1.53 m

xM , xm =0.384 m, 1.53 m

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