A telescope consisting of a +3.0-cm objective lens and a +0.35-cm eyepiece is us

Question

A telescope consisting of a +3.0-cm objective lens and a +0.35-cm eyepiece is used to view an object that is 20 m from the objective lens.

Part A

What must be the distance between the objective lens and eyepiece to produce a final virtual image 100 cm to the left of the eyepiece?

Express your answer to two significant figures and include the appropriate units.

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Part B

What is the total angular magnification?

Express your answer using two significant figures.

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A telescope consisting of a +3.0-cm objective lens and a +0.35-cm eyepiece is used to view an object that is 20 m from the objective lens.

Part A

What must be the distance between the objective lens and eyepiece to produce a final virtual image 100 cm to the left of the eyepiece?

Express your answer to two significant figures and include the appropriate units.

d =

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Part B

What is the total angular magnification?

Express your answer using two significant figures.

M =

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Explanation / Answer

given,

focal length of objective lens = 3 cm

focal length of eyepiece lens = 0.35 cm

distance of object = 20 cm

from lens equation

1 / f = 1 / u + 1 / v

1 / 3 = 1 / 20 + 1 / v

v = 3.5294 cm

its magnification = - distance of image / distance of object

magnitication m1 = 3.5294 / 20

virtual image is 100 cm leeft to eyepiece

1 / 0.35 = -1 / 100 + 1 / u

u = 0.34878 cm

magnification m2 = 100 / 0.34878

d = u + v

d = 3.5294 + 0.34878

d = 3.87818 cm

total angular magnification = m1.m2

total angular magnification = 3.5294 / 20 * 100 / 0.34878

total angular magnfication = 50.5963

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