The figure below shows a bar of mass m0.260 kg that can slide without friction o

Question

The figure below shows a bar of mass m0.260 kg that can slide without friction on a pair of rails separated by a distance ?-1.20 m and located on an inclined plane that makes an angle = 27.00 with respect to the ground. The resistance of the resistor is R = 1.80 and a uniform magnetic field of magnitude B = 0.500 T is directed downward, perpendicular to the ground, over the entire region through which the bar moves. With what constant speed v does the bar slide along the rails? Your response differs from the correct answer by more than 10%. Double check your calculations. m/s 14.31

Explanation / Answer

flux = vtlsin(theta)

emf = change in flux per unit time = vlsin(theta)

I = emf/R = vlsin(theta)/R

So magnatic force = gravitational force

=> ILXBcos(theta) = mgSin(theta)

=> vLsin(theta)*L*B*cos(theta)/R = mg sin(theta)

=> v = 0.26*9.81*1.8/(1.2*1.2*0.5*cos(27)) = 7.156 m/s Answer

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