The figure below shows a 100N force applied at a 15 degree angle to the handle o

Question

The figure below shows a 100N force applied at a 15 degree angle to the handle of the jaws. What would be the magnitude of force applied perpendicular to the handle of the jaws? A robot arm can be represent by two lines, one from the shoulder joint at point A to the elbow at point B and the other line from the elbow at point B to the wrist at point C, if the locations of the shoulder elbow, and wrists are given below, what is the length of the (AB) and lower arm (AC) and the angel theta and phi Locations of joints in inches A (0, 0) B (12, -9) C (25, -4)

Explanation / Answer

MAGNITUDE of perpendicular force to the handle in either handle = cos component of the force
Force, F = 100 N
Perpendicular force, F' = Fcos(15) = 100cos(15) = 96.592 N
MOment about origin = perpendicular distance * Perpendicular force = 400mm * 96.592 N = 38.63 Nm

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