A wire (mass = 50 g, length = 40 cm) is suspended horizontally by two vertical w

Question

A wire (mass = 50 g, length = 40 cm) is suspended horizontally by two vertical wires which conduct a current I = 8.0 A, as shown in the figure. The magnetic field in the region is into the paper and has a magnitude of 60 mT. What is the tension in either wire? A charged particle (m = 5.0 g, q = - 70 mu C) moves horizontally at a constant speed of 30 km/s in a region where the free fall gravitational acceleration is 9.8 m/s^2 downward, the electric field is 700 N/C upward, and the magnetic field is perpendicular to the velocity of the panicle. What is the magnitude of the magnetic field in this region?

Explanation / Answer

Force due to magnetic field

Fb = Bil (vertically downward

Fb =0.192

Therefore

For equilibrium

2T = mg + Fb

2T = 0.682

T = 0.341N

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