A wildlife manager is trying to raise pheasants to stock out as part of a pheasa

Question

A wildlife manager is trying to raise pheasants to stock out as part of a pheasant recovery program. To maximize her yield she maintains a population at 700 birds. 'Maximum population growth occurs at K/2 so K her artificial is 1400 birds. Calculate the growth rate of the population if she receives a donation of 550 additional birds for her program. The r for the pheasant population is 0.06 (pheasants/day). Questions adapted from Sarah E. Brocia, Krissy Dilustro and Anna M. Lovrien via the AP Biology Teacher Community.

Explanation / Answer

Population growth rate will be –

dN/dT = r*[(K-N)/K]*N            

[Here, dN/dT = population growth rate, r=per capita rate, (K-N)=more individuals added, K=carrying capacity, N=total no. of population]

dN/dT = 0.06*[550/1400]*700 = 16.5

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.