A 5.0 kg toy car can move along an x axis. The figure gives Fx of the force acti

Question

A 5.0 kg toy car can move along an x axis. The figure gives Fx of the force acting on the car, which begins at rest at time t = 0. The scale on the Fx axis is set by Fxs = 6.0 N. In unit-vector notation, what is Upper P Overscript right-arrow EndScripts at (a)t = 8.0 s and (b)t = 5.0 s,(c) what is v Overscript right-arrow EndScripts at t = 6.0 s?

X AE Aeronautical Engineering x Wiley PLUS C fi eduge Apps H Sig in to office 365 my LSU -single sig U Ub 864 Wiley PLUS Halliday, Fundamentals of Physics, 10e Assignment open Assignment Fo of rce acting on the c begins at re g toy (a) Number i Units (b) Number J Units (c) Number i j k Units timet 0, The scale on the F axis i F (N Physics (1202/2110/2112/2113) PRINTER VERSION BACK INEXT ion, what is P at (a)t 8.0 s and (b 5.0 s,(c) what is v version 4.17.3.3 10:20 PM ENG 3/29/2016

Explanation / Answer

Initial momentum , Pi = 0 Kg.m/s

initial velocity , u = 0 m/s

as change in momentum = area under the Force-time curve

a) at t = 8 s

change in momentum = arrea under the curve

P - Pi = 2 * 6 * 0.5 * 2 + 2 * 6 * 2 + 2 * 6 * 0.5 * 2 - 0.5 * 5 * 1 - 6 * 1

P = 39.5 i Kg.m/s

the momentum P is 39.5 i Kg.m/s

b) at t = 5 s

change in momentum = arrea under the curve

P - Pi = 2 * 6 * 0.5 * 2 + 2 * 6 * 2 + 2 * 6 * 0.5 * 2 - 0.5 * 5 * 1

P = 45.5 i Kg.m/s

the momentum P is 45.5 i Kg.m/s

c) at t = 6 s

let the velocity is v

change in momentum = arrea under the curve

P - Pi = 2 * 6 * 0.5 * 2 + 2 * 6 * 2 + 2 * 6 * 0.5 * 2

m * v = 39.5 i Kg.m/s

5 * v = 48 i

v = 9.6 i m/s

the speed of the car is 9.6 i m/s

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