A 5.0 ? resistor is connected in series with a 10.0 ?resistor. This combination

Question

A 5.0 ? resistor is connected in series with a 10.0 ?resistor. This combination is then connected in parallel witha 7.5 ? resistor. The three resistor network is then connectedin series with a 15 ? resistor. The entire circuit is thenattached to the terminals of a 50 V power supply. Calculatethe following:

a. The total equivalent resistance between theterminals.

b. The potential across each of the resistors.

c. The current through each of the resistors.

d. The total power dissipated by this circuit..

Thanks for helping me with this problem.Please remember there are 4 PARTS to this problem andall 4 parts need to be included in your answer.

Explanation / Answer

The first thing that you need to do is calculate total resistanceby looking at which resistors are in parallel and series A)5 + 10 = 15 1/15 + 1/7.5 = 5 5 + 15 = 20 B) and C) Current in a series circuit doesn't change so first calculate totalcurrent in the circuit. I = V/R = 2.5A and since current doesn't change in a seriescircuit, the current going through the 15 resistor is 2.5Aand the voltage is V = IR = 37.5V. The remaining voltage must be applied to both branches of theparallel circuit so the voltage drop across the 7.5 resistormust be 12.5V and the current will be I = V/R = 1.67A. In the other branch, the 12.5V will be split between the tworesistors. The current going through both of them will be I =V/R = 12.5V/15 = 0.83A so for the 10 resistor V = IR = 0.83A * 10 = 8.3V so for the 5 resistor V = IR = 4.15V To sum these up 7.5: V = 12.5V, I = 1.67A 10: V = 8.3V, I = 0.83A 5: V = 4.15V, I =0.83A 15: V = 37.5V, I = 2.5A D. P=IV = 2.5A * 50V = 125Watts Hope that helps

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