An electron with an initial speed of 460,000 m/s is brought to rest by an electr

Question

An electron with an initial speed of 460,000 m/s is brought to rest by an electric field.

Did the electron move into a region of higher potential or lower potential?

Did the electron move into a region of higher potential or lower potential?

Because the electron is a negative charge and it slows down as it travels, it must be moving from a region of higher potential to a region of lower potential.

What was the potential difference that stopped the electron?

What was the initial kinetic energy of the electron, in electron volts?

Because the electron is a negative charge and it slows down as it travels, it must be moving from a region of lower potential to a region of higher potential. Because the electron is a positive charge and it accelerates as it travels, it must be moving from a region of higher potential to a region of lower potential. Because the electron is a positive charge and it accelerates as it travels, it must be moving from a region of lower potential to a region of higher potential.

Because the electron is a negative charge and it slows down as it travels, it must be moving from a region of higher potential to a region of lower potential.

What was the potential difference that stopped the electron?

What was the initial kinetic energy of the electron, in electron volts?

Explanation / Answer

to brought to rest, Electric field must be applied in opposite direction of velocity.

and Fe = qE

q is negative for electron.

so E will be in same direction as velocity.

Field direction is higher potential to lower potential .

so electron will move from higher potential to lower potential .

Ans. Because the electron is a negative charge and it slows down as it travels, it must be moving
from a region of higher potential to a region of lower potential

suppose potential difference is V. then

initial KE = - qV

9.109 x 10^-31 x 460000^2 /2 = 1.6 x 10^-19 x V

V = 0.602 volt .........Ans

initial KE of electron = qV = 1e ( 0.603 volt) = 0.603 eV

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