It is a question related to physics lab (Conservation of Momentum) 7.5 Prelimina
ID: 1429186 • Letter: I
Question
It is a question related to physics lab (Conservation of Momentum) 7.5 Preliminary Assignment Car A ofmass (30 1.1 ±0.1)s has an initial speed of (2.12±0.03)% and moves in the positive X direction. Car B of mass (305.3±0.1)g is initially stationary. The two cars collide. After the collision, car A comes to a stop and car B has a speed of (1.97±0.02)% in the positive X 1) direction. A) Calculate the total initial momentum of the two car system with uncertainty. B) Calculate the total final momentum of the two car system with uncertainty. C) Is momentum conserved? (Hint: Don't just answer 'yes or 'no'.) D)Cas h ras id E) Calculate the total final kinetic energy of the two car system with uncertainty. F) Is this an elastic collision? (Hint: Don't just answer 'yes' or 'no')Explanation / Answer
Given that
Ma = (301.1 _+0.1) g , ua = (2.12 _+ 0.03) m/s , va= 0
Mb = (305. 3 _+ 0.1) g , ub = 0 , vb = (1.97 _+ .02) m/s
(A) initial linear momentum of two car system = initial linear momentum of car A ( because car B is at rest initially)
Pi = ma ub along positive x axis
= ( 0.638 _+0.0092) kgm/s
(B) final linear momentum of two car system = final linear momentum of car B ( because finally car A comes at rest)
Pf = mb vb along positive x axis
= (0.601 _+0.006) kg m/s
(C) we can see that the direction of final and initial linear momentum is same but the magnitude of final momentum is less than initial momentum . So momentum is not conserved .
(D) initial kinetic energy of system = initial kinetic energy of car A ( because car B was at rest initially)
Ki = 1/2 ma ua ^2 = (0.676 _+ 0.019) j
(E) final kinteic energy of system = final kinetic energy of car B ( because car A comes at rest finally)
Kf = 1/2 mb vb 2 = (0.592 _+ 0.012) j
(D) one can easily see that fianl kinetic energy is less then initial kinetic energy it means kinetic energy is lost during collision so it can not be an elastic collision .
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