The electrostatic force acting on the particle has a magnitude of: The electrost

Question

The electrostatic force acting on the particle has a magnitude of:

The electrostatic force exerted on the particle by the uniform electric field is directed:

During the period of time it takes the particle to travel a distance of 200 mm parallel to the electric field, the work done on the particle by the electrostatic force is equal to:

The final kinetic energy of the particle is equal to:

The constant acceleration experienced by the particle has a magnitude of:

The constant acceleration experienced by the particle is directed:

How much time did it take the particle to travel the 200 mm parallel to the uniform electric field?

The particle’s final speed is equal to:

A negatively charged particle of mass m=589x10-23 g and q=-L60x10-19C is immersed in a uniform 150x 103 NIC electric field pointing in the positive x direction, as shown in the figure. The particle is initially traveling parallel to the uniform electric field at a speed of 1.00x 105 m/s. Assume that the gravitational force acting on the particle is negligible compared to the electrostatic force acting on it. Consider a period of time during which the particle travels a distance of 2.00x 102 mm parallel to the uniform electric field. uniform (1500 NC) Vi 200 mm

Explanation / Answer

You have an initial figure, but not see it.

The electrostatic force acting on the particle has a magnitude of:

product of the charge by the electrical field

The electrostatic force exerted on the particle by the uniform electric field is directed:

in the same direction of the field if the charge is positiva and contrary to sense if the particle field tine negative charge

During the period of time it takes the particle to travel a distance of 200 mm parallel to the electric field, the work done on the particle by the electrostatic force is equal to:

producing the electric force by the distance qE d

The final kinetic energy of the particle is equal to:

½ m v2 = ½ m ( 2 (qE/m) X) = q E X

The constant acceleration experienced by the particle has a magnitude of:

product load by the electric field divided by the mass

The constant acceleration experienced by the particle is directed:

in the same direction of the electric field if the particle has a positive charge and opposite to the field if the charge is negative

How much time did it take the particle to travel the 200 mm parallel to the uniform electric field?

We use the expression kinematics Vo = 0 where time is the square root of 2 divided acceleration distance

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