The electron in the figure below is traveling with a speed of v = 2 × 106 m/s. (

Question

The electron in the figure below is traveling with a speed of v = 2 × 106 m/s. (Assume 700 and r= 6 × 10-10 m.) 1- Electron (a) At location A, what is the direction of the electric field contributed by the electron? O The direction of electric field is away from the electron. O The direction of electric field is toward the electron O The direction of electric field is into the page. O The direction of electric field is out of the page. At location A, what is the direction of the magnetic field contributed by the electron? O The direction of magnetic field is away from the electron. The direction of magnetic feld is toward the electron O The direction of magnetic field is into the page. O The direction of magnetic field is out of the page (b) Calculate the magnitudes of the electric and magnetic fields at location A IEI = BI = N/C

Explanation / Answer

a)

The direction of electric field is towards the electron'b)

b)

The direction of magnetic field is out of the page

c)

The Magnitude of electric field Is

E=Kq/r2=(9*109)(1.6*10-19)/(6*10-10)2

E=4*109N/C

The magnitude of magnetic field is

B=(uo/4pi)(qvsino/r2)

B=(4pi*10-7/4pi)(1.6*10-19*2*106)(sin70)/(6*10-10)2

B=0.0835 T

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