A 5.25 F capacitor is initially charged to a potential of 16.4 V . It is then co

ID: 1426168 • Letter: A

Question

A 5.25 F capacitor is initially charged to a potential of 16.4 V . It is then connected in series with a 3.80 mH inductor.

Part A

What is the total energy stored in this circuit?

Express your answer in joules to three significant figures.

Part B

What is the maximum current in the inductor?

Express your answer in amperes to three significant figures.

Part C

What is the charge on the capacitor plates at the instant the current in the inductor is maximal?

Express your answer in microcoulombs to the nearest integer.

here,

capacitor , C = 5.25 * 10^-6 F

V = 16.4 V

inductance , L = 0.0038 H

the total energy stored in this circuit , E = 0.5 * C * V^2

E = 0.5 * 5.25 * 10^-6 * 16.4^2

E = 7.06 * 10^-4 J

the total energy stored in this circuit is 7.06 * 10^-4 J

let the maximum current be I

0.5 * L * I^2 = 0.5 * C * V^2

0.0038 * I^2 = 0.5 * 5.25 * 10^-6 * 16.4^2

I = 0.431 A

the maximum current is 0.431 A

when the current is maximum across inductor,

the voltage across capacitor is zero ,

then the charge across the plates is zero

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