A 5.00-g lead BB moving at 44.0 m/s penetrates a wood block and comes to rest in
ID: 1294643 • Letter: A
Question
A 5.00-g lead BB moving at 44.0 m/s penetrates a wood block and comes to rest inside the block. If half of its kinetic energy is absorbed by the BB, what is the change in the temperature if the BB? The specific heat of lead is 128 J/kg A 5.00-g lead BB moving at 44.0 m/s penetrates a wood block and comes to rest inside the block. If half of its kinetic energy is absorbed by the BB, what is the change in the temperature if the BB? The specific heat of lead is 128 J/kg A 5.00-g lead BB moving at 44.0 m/s penetrates a wood block and comes to rest inside the block. If half of its kinetic energy is absorbed by the BB, what is the change in the temperature if the BB? The specific heat of lead is 128 J/kgExplanation / Answer
0.5* m* v2 * 0.5 = m* cp* delta T
delta T= 0.25 * 442 / 128
= 3.78 K (B is correct )
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