A 5.00 g bullet traveling horizontally at 430 m / s is shot through a 2.00 k g w

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A 5.00g bullet traveling horizontally at 430m/s is shot through a 2.00kg wood block suspended on a string 3.00m long. Part A If the center of mass of the block rises a distance of 0.350cm , find the speed of the bullet as it emerges from the block. v = m/s SubmitMy AnswersGive Up A 5.00g bullet traveling horizontally at 430m/s is shot through a 2.00kg wood block suspended on a string 3.00m long. A 5.00g bullet traveling horizontally at 430m/s is shot through a 2.00kg wood block suspended on a string 3.00m long. A 5.00g bullet traveling horizontally at 430m/s is shot through a 2.00kg wood block suspended on a string 3.00m long. A 5.00g bullet traveling horizontally at 430m/s is shot through a 2.00kg wood block suspended on a string 3.00m long. Part A If the center of mass of the block rises a distance of 0.350cm , find the speed of the bullet as it emerges from the block. v = m/s SubmitMy AnswersGive Up Part A If the center of mass of the block rises a distance of 0.350cm , find the speed of the bullet as it emerges from the block. v = m/s SubmitMy AnswersGive Up Part A If the center of mass of the block rises a distance of 0.350cm , find the speed of the bullet as it emerges from the block. v = m/s SubmitMy AnswersGive Up Part A If the center of mass of the block rises a distance of 0.350cm , find the speed of the bullet as it emerges from the block. v = m/s SubmitMy AnswersGive Up Part A If the center of mass of the block rises a distance of 0.350cm , find the speed of the bullet as it emerges from the block. v = m/s SubmitMy AnswersGive Up Part A If the center of mass of the block rises a distance of 0.350cm , find the speed of the bullet as it emerges from the block. v = m/s SubmitMy AnswersGive Up v = m/s v = m/s SubmitMy AnswersGive Up A 5.00g bullet traveling horizontally at 430m/s is shot through a 2.00kg wood block suspended on a string 3.00m long. Part A If the center of mass of the block rises a distance of 0.350cm , find the speed of the bullet as it emerges from the block. v = m/s SubmitMy AnswersGive Up

Explanation / Answer

From Energy conservation 1/2 mu^2-1/2mv^2 = Mgh

mv^2 = mu^2-Mgh

v^2 = u^2 - (M/m )gh

= 430^2 - (2/0.005)*9.8*0.0035

= 184900 - 13.72

= 429.98 m/s

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