A pair of closely spaced parallel conducting plates, charged with equal and oppo

Question

A pair of closely spaced parallel conducting plates, charged with equal and opposite electric charges, produces a uniform electric field in the region between them. In designing a cutting-edge device that will revolutionize the electronics industry, you set up such a pair of plates with a separation of 0.839 mm between them and charge them so that the direction of the electric field in their interior region is from plate A to plate B. Your idea requires that electrons, when released from rest at one of the plates, reach the other plate at the speed of 1.45% of the speed of light. (The speed of light is c = 3.00 times 10^8 m/s.) At which plate should the electrons be released?

Explanation / Answer

Electron has to be released at B because it moves opposite to field

Ee = ma

E= ma/e

to find a,

v2 = u2 + 2as

(3*108 *1.45/100)2 =2 a *8.39* 10-4

a = 18.92 *1016 /(2*8.39) = 1.127 * 1016

E= ma/e

  = 9.1 *10-31 *1.13*1016 / 1.6*10-19

= 64268 N/C

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