A truck driver has a shipment of apples to deliver to a destination 495 miles aw

Question

A truck driver has a shipment of apples to deliver to a destination 495 miles away. The trip usually takes him 9.00 hours . Today he finds himself daydreaming and realizes 130 miles into his trip that that he is running 20.0 minutes later than his usual pace at this point. At what speed must he drive for the remainder of the trip to complete the trip in the usual amount of time?
A truck driver has a shipment of apples to deliver to a destination 495 miles away. The trip usually takes him 9.00 hours . Today he finds himself daydreaming and realizes 130 miles into his trip that that he is running 20.0 minutes later than his usual pace at this point. At what speed must he drive for the remainder of the trip to complete the trip in the usual amount of time?
A truck driver has a shipment of apples to deliver to a destination 495 miles away. The trip usually takes him 9.00 hours . Today he finds himself daydreaming and realizes 130 miles into his trip that that he is running 20.0 minutes later than his usual pace at this point. At what speed must he drive for the remainder of the trip to complete the trip in the usual amount of time?

Explanation / Answer

usual average speed of the truck for total trip, t = 495/9

= 55 mi/hr

while daydreaming,
time taken him to travel for 130 miles, t1 = (20/60) + 130/55

= 2.7 hours

so, remaining time, t2 = t - t1

= 9 - 2.7

= 6.3 hours.

s0, the speed must he drive for the remainder of the trip to complete the trip in the usual amount of time = remaining distance/time taken

= (495-130)/6.3

= 57.94 mi/hr

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