A particle with a charge of 33 C moves with a speed of 73 m/s in the positive x

Question

A particle with a charge of 33 C moves with a speed of 73 m/s in the positive x direction. The magnetic field in this region of space has a component of 0.39 T in the positive y direction, and a component of 0.87 T in the positive zdirection.

Part A

What is the magnitude of the magnetic force on the particle?

Express your answer using two significant figures.

Part B

What is the direction of the magnetic force on the particle? (Find the angle measured from the positive z-axis toward the negative y-axis in the yz-plane.)

Express your answer using two significant figures.

Explanation / Answer

A) Apply, F = q*(v cross B)

= 33*10^-6*( 73 i cross (0.39 j + 0.87 k) )

= 33*10^-6*( 73*0.39 k - 73*0.87 j)

= (-2.095*10^-3 j + 0.9395*10^-3 k ) N

so, |F| = sqrt(2.095^2 + 0.9395^2)*10^-3

= 2.30*10^-3 N

B) theta = tan^-1(2.095/0.9395)

= 65.85 degrees

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