A particle that carries a net charge of -23.8 held in a region of constant, unif

Question

A particle that carries a net charge of -23.8 held in a region of constant, uniform electric field.

a) How much work is done by the electric field as the particle is made to move a distance d=0.556m straight up?

b) What is the potential difference between the particles initial and final positions (Vf - Vi)?

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A particle that carries a net charge of -23.8 uC is held in a region of constant, uniform electric field. The electric field vector is oriented 40.20 clockwise from the vertical axis, as shown. If the magnitude of the electric field is 8.82 NIC, how much work is done by the electric field as the particle is made to move a distance of d 0.556 m straight up? Number 40.2 What is the potential difference between the particle's initial and final positions (V- V)? Number

Explanation / Answer

1)

W = Eqdcos = (8.82N/C)(-23.8*10-6C)(0.556)cos(40.2) = -8.91*10-5 J

2)


V = U / q = W / q = (-8.91*10-5J) / (-23.8*10-6C) = 3.746 V

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