A particle of unknown charge q and unknown mass m moves at a speed of 4.8 x1 10^

Question

A particle of unknown charge q and unknown mass m moves at a speed of 4.8 x1 10^6 m/s in the +x direction into a region of constant magnetic field. The field has a magnitude of 0.5 T and is oriented in the +z direction. The particle is deflected in the -y direction and traces out of a fragment of a circle of radius 0.1m. a) What is the ratio q/m and what is the sign of the particles charge? b) The velocity of a particle described in part a) is changed so that its x-component is as before but there is an additional component of 2.4 x 10^5 m/s in the +z direction. What is the pitch of the resulting spiral (the axial distance traveled during one revolution)?

Explanation / Answer

thus, the force exerted will cause te charge to move in circles but the velocity in the z-direction will also cause it to move upwards and hence, the "spiral" shape as mentioned in question. let's rearrange the original formula to take centripetal force as mr?^2. Thus, mr?^2 = Bqv. Remember that ? = 2pi/T where T is time period of time taken for 1 revolution. We need to find basically how much distance will be travelled in this time T. the distance travelled will be velocity into time as velocity is constant. hence, distance = 2.4 x 10^5 x T.

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