A large research solenoid has a self-inductance of 3 H. Randomized Variables L =

Question

A large research solenoid has a self-inductance of 3 H.

Randomized VariablesL = 3 H
I = 125 A
t = 77.5 ms

A) What is the magnitude of the EMF, in kilovolts that opposes shutting off a current of 125 A through the selenoid in 77.5 ms?

B)How much energy in joules is stored in the inductor at full current?

C)At what rate, in megawatts, must energy be dissipated when the full current is switched off in 77.5 ms?

(7%) Problem 15: A large research solenoid has a self-inductance of 3 H. Randomized Variables L=3H I= 125 A 775 ms 33% Part (a) What is the magnitude of the emf in kilovolts, that opposes shutting off a current of 125 A through the solenoid in 77.5 ms? - 33% Part (b) How much energy in joules is stored in the inductor at full current? 33% Part (c) At what rate, in megawatts, must energy be dissipated when the full current is switched off in 775 ms?

Explanation / Answer

A) emf e = L*di/dt = 3*(125)/(77.5*10^-3) = 4.84 kV

B) U = 0.5*L*i^2 = 0.5*3*125^2 =2.34*10^4 J

C) power dissipation P = e*i = 4.84*1000*125 = 0.605 MW

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