A) A hydrogen atom in the n =6 state decays to the n =4 state. What is the wavel

Question

A) A hydrogen atom in the n=6 state decays to the n=4 state. What is the wavelength of the photon that the hydrogen atom emits?

2629 nm (Correct)

B) While in the first excited state, a hydrogen atom is illuminated by various wavelengths of light. What happens to the hydrogen atom when illuminated by each wavelength?

486.3 nm? jumps to n=4 state (Correct)

325.4 nm? stateis ionized (Correct)

498.4 nm? (Do not get this one, either one of three is right)

stays in n=2 state

jumps to n=5 state

jumps to n=6 stateis ionized  

Guide me through this please :D

Explanation / Answer

for last Part:

use the formula of wavelegnth 1/L = R *(1/n^2-1/m^2)

here n =2    m = ?

wavelength L = 498.4 e-9 m

Rydberg constant R = 1.1 e 7

so

1/n^2 -1/m^2 = 1/(1.1 e7 * 498.4 e-9)

1/n^2 -1m^2 = 0.182

1/m^2 = 1/2^2 + 0.182

1/m^2 =0.182 -0.25

m^2 = 1/ 0.068

m^2 = 14.76

m = 4

so as it in excited state, answer is n = 5 state

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