Two identical strings are under different amounts of tension. The fundamental fr

Question

Two identical strings are under different amounts of tension. The fundamental frequency of string A is twice the fundamental frequency of string B. How do the magnitudes of the tension in each string compare?

A) The tension in string A is greater than in string B, but less than twice the magnitude.

B) The tension in string A is four times the magnitude of the tension in string B.

C) The tension in string A is less than in string B, but greater than half the magnitude.

D) The tension in string A is twice the magnitude of the tension in string B.

E) The tension in string A is between two and four times the magnitude of the tension in string B.

Explanation / Answer

frequency of string

f=sqrt(k/m)/2pi

from above relation frequency is inversely propotional to mass

fa/fb  =sqrt(m2/m1)

fa=2fb

4=m2/m1

m2=4m1

B is ANSWER

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