Two identical strings are sounding the same fundamental tone of frequency 156 Hz

Question

Two identical strings are sounding the same fundamental tone of frequency 156 Hz. Each string is under 230 N of tension. The peg holding one string suddenly slips, reducing its tension slightly, and the two tones now create a beat frequency of three beats per second. What is the new tension in the string that slipped? Two identical strings are sounding the same fundamental tone of frequency 156 Hz. Each string is under 230 N of tension. The peg holding one string suddenly slips, reducing its tension slightly, and the two tones now create a beat frequency of three beats per second. What is the new tension in the string that slipped?

Explanation / Answer

as the tenion in the string decreases then frequency of the string also decreases

after reducing tension the new frequency of the strig is 153 Hz

from the equation f = (1/2L)sqrt(T/mu)

f1/f2 = sqrt(T1/T2)

156/153 = sqrt(230/T2)

1.039 = 230/T2

T2 = 230/1.039 = 221.4 N

is the new tension of the string

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