Two identical positive charges are placed 15 cm apart and the magnitude of the e

Question

Two identical positive charges are placed 15 cm apart and the magnitude of the electric force between them is 5.4 Newtons. They then exchange charge (one charge loses some electrons and the other gains the same amount of electrons), but they both still remain positive. After they have exchanged charge and are placed 15 cm apart the magnitude of the electric force is now 3.8 Newtons. How much charge, in micro-coulombs, was exchanged? Use the absolute value of the charge exchanged so the answer is positive.

Explanation / Answer

The force between two point charges is given by F = (k)(q1)(q2) / (r2) where k = 9.0 * 109 substituting q1=q2 and r = 4.0 * 10-10 and F = 5.6 * 10-9 then solving for q leads to a value of q = 9.97 * 10-19

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