Two identical masses, 25.0kg each, are connected through an ideal string and an

Question

Two identical masses, 25.0kg each, are connected through an ideal string and an ideal pulley as shown. The angles are theta = 30.0 degree and gamma = 60.0 degree. (I) Draw one free body diagram for each of the two masses, with the positive horizontal direction corresponding to the direction of motion. (II)The magnitude of the acceleration of the blocks is A. 0.60 m/s^2. B. 3.47 m/s^2 C. 1.96 m/s^2. D. 1.80 m/s^2 E. 2.37 m/s^2 (III) If the blocks start from rest, the time required to move a distance of 98.0 cm IS A. 0.752s. B. 1.42s C. 1.04s D. 0.909s E. 1.80s.

Explanation / Answer

let the tension in the string = T

let's devlop equations of motion for both masses

25 (a) = 25 (9.8) sin 60 - T

25 a= 212.176 - T -----------eq(1)

25(a) = T - 25 (9.8) sin 30

25(a) = T - 122.5 ----------eq(2)

adding eq (1) , and (2)

50 a= 89.676

a= 1.79 m/s^2 apprx ( option D)

b) s = 1/2 at^2

0.98 = 0.5 ( 1.80) t^2

t = 1.04 sec ( option C)

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.