Two identical pucks are on an air table. Puck A has an initialvelocity of 2.3 m/

Question

Two identical pucks are on an air table. Puck A has an initialvelocity of 2.3 m/s in the positivex-direction. Puck B is at rest. Puck A collideselastically with puck B and A moves off at 1.0 m/s at an angle of +60° above thex-axis. What is the speed and direction of puck B afterthe collision? (Let angles above the +x-axis to bepositive and below to be negative.) magnitude ___ m/s direction ___ degrees Two identical pucks are on an air table. Puck A has an initialvelocity of 2.3 m/s in the positivex-direction. Puck B is at rest. Puck A collideselastically with puck B and A moves off at 1.0 m/s at an angle of +60° above thex-axis. What is the speed and direction of puck B afterthe collision? (Let angles above the +x-axis to bepositive and below to be negative.) magnitude ___ m/s direction ___ degrees

Explanation / Answer

If two identical pucks collide elastically, the angle between themafter the collision is 90 degrees so puck B goes off at an angleof 30 degrees below the x-axis. So the momentum along thex-axis is m(2.3) = mv1cos(60) +mv2cos(30) momentum vertically is given by mv1sin(60) =mv2sin(30) work it out from here

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