Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

1a) When a portable fan is first turned on it draws 4.25 A (rms current). After

ID: 1374287 • Letter: 1

Question

1a) When a portable fan is first turned on it draws 4.25 A (rms current). After it has come up to speed it draws 0.60 A (rms current). Assuming the fan runs off a 120 V (rms) outlet, calculate the back emf while the motor is running.

1b) A very long solenoid with a circular cross section and radius r1= 1.20 centimeters with ns= 300. turns/cm lies inside a short coil of radius r2= 4.50 centimeters and Nc= 27 turns.

If the current in the solenoid is ramped at a constant rate from zero to Is= 2.80 Amperes over a time interval of 95.0 milliseconds, what is the magnitude of the emf in the outer coil while the current in the solenoid is changing?

1a) When a portable fan is first turned on it draws 4.25 A (rms current). After it has come up to speed it draws 0.60 A (rms current). Assuming the fan runs off a 120 V (rms) outlet, calculate the back emf while the motor is running. 1b) A very long solenoid with a circular cross section and radius r1= 1.20 centimeters with ns= 300. turns/cm lies inside a short coil of radius r2= 4.50 centimeters and Nc= 27 turns. If the current in the solenoid is ramped at a constant rate from zero to Is= 2.80 Amperes over a time interval of 95.0 milliseconds, what is the magnitude of the emf in the outer coil while the current in the solenoid is changing?

Explanation / Answer

1)

a)

120 = 4.25 * R

R = 28.23

120 = E + 0.6*R

E = 120 - 0.6 * 28.23 = 103.062 V

b)

e = A*N2*N1*uo*di/dt

= 3.14*0.045^2*27*30000*4*pi*10^-7*2.80/95*10*10^-3

= 0.1908 V

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote