A thin, converging lens whose focal length is 79 cm is placed 4.8 m from a conve

Question

A thin, converging lens whose focal length is 79 cm is placed 4.8 m from a convex spherical mirror whose focal length is

?45 cm

(see figure below). For an object placed 1.2 m to the left of the lens, determine the location of the image formed by the mirror, the magnification of the image, and the nature of the image (real/virtual, upright/inverted, enlarged/reduced). Hint: Use the image formed by the lens as the object for the mirror.

(a) the location of the image formed by the mirror

(b) the magnification of the image?


(c) the nature of the image (Select all that apply.)

real

virtual

upright

inverted

enlarged

reduced

|distance|     ?????? cm location     in front of the mirror or behind the mirror A thin, converging lens whose focal length is 79 cm is placed 4.8 m from a convex spherical mirror whose focal length is ?45 cm (see figure below). For an object placed 1.2 m to the left of the lens, determine the location of the image formed by the mirror, the magnification of the image, and the nature of the image (real/virtual, upright/inverted, enlarged/reduced). Hint: Use the image formed by the lens as the object for the mirror. (a) the location of the image formed by the mirror |distance| ?????? cm location in front of the mirror or behind the mirror (b) the magnification of the image? (c) the nature of the image (Select all that apply.) real virtual upright inverted enlarged reduced

Explanation / Answer

first for lens u = objetc distance = 1.2 m

f = 79 cm

use 1/f = 1/u +1/ v

so 1/v = 1/f   - 1/u

v = uf/(u-f)

v = 1.2* 0.79/(1.2-0.79)

v = 2.31 m

so object distance for mirror is u = 4.8-2.31 = 2.48 m

f = 0.45 m

so

final image is formed at v = uf/U-f

v = (2.48 * 0.45)/(2.48 -0.45)

v = 0.549 m or 55 cm
-------------------

magnification m = -v/u

m = -55/120

m = -0.458

as m is -ve, this must be a virtual, inverted and reduced image

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.