A horizontal uniform magnetic field of magnitude 0.6 T is oriented at an angle o

Question

A horizontal uniform magnetic field of magnitude 0.6 T is oriented at an angle of Tau net = NA.m c.) Find the net magnetic torque (size & direction) experienced by the loop when it is initially released as shown above. Give direction according to the top view. (Highly recommended: Use the normal vector shortcut.) Theta = 65 degree relative to a line perpendicular to plane of a vertical, rectangular loop, as indicated in the figure. The loop has a height of 8 cm and a width of 15 cm. Each of the 1000 turns of wire in the loop carries a current of 0.24 A counterclockwise around it.

Explanation / Answer

B = 0.6 T

Area, A = 8*15 cm2 = 120 cm2 = 0.012 m2

N = 1000

Q = 65 degrees

current = I = 0.24 A

Torque, T = BINA*sin(Q)

So, T = 0.6*0.24*1000*0.012*sin(65 degrees)

= 1.566 N.m <--------------answer

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