A horizontal venturi flow meter consists of a converging-diverging conduit. The

Question

A horizontal venturi flow meter consists of a converging-diverging conduit.  The diameters of cross section (1)= 6 in and (2) = 4 in.  The velocity and static pressure are uniformily distributed at cross sections (1) and (2).  Determine in the volume flowrate (ft^3/s) through the meter if p1-p2=3 psi, the flowing fluid is oil (density = 56 lb*m/ft^3), and the loss per unit mass from (1) to (2) is negligibly small.

Explanation / Answer

Given conditions : the tube is horizontal so no change inpotential Energy due to g    change in pressure= 3psi                                density of liquid =56 lbm/ft3                                 diameters d(1) =6 d(2)=4 So adjusted equation is P1+ V12/2 =P2 + V22/2  =>      P=/2(V(1)^2-V(2)^2) where volume flow rate is V= Q/A =4Q/*d*d applying 3 =( 56/12*12)(8Q2/2)[34 -24] Which gives Q/ =0.121 which gives Q =0.381Ft^3/s

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