An electron in a cathode-ray tube is accelerated through a potential difference

Question

An electron in a cathode-ray tube is accelerated through a potential difference of 10 kV, then passes through the d = 1.6-cm-wide region of uniform magnetic field in the figure. What field strength will deflect the electron by ? = 14??

B= ___________

An electron in a cathode-ray tube is accelerated through a potential difference of 10 kV, then passes through the d = 1.6-cm-wide region of uniform magnetic field in the figure. What field strength will deflect the electron by ? = 14?? B= ___________

Explanation / Answer

Here ,

V = 10 kV

let the speed of electron is v

0.5 * 9.1 *10^-31 * v^2 = 10 *10^3 * e

v = 5.934 *10^7 m/s

Now, for theta = 14 degree

Now, for d = 1.6 cm

2*pi*r * 14/360 = 1.6

r = 6.55 cm

Now, as r = mv/B*q

0.0655 = 9.1 *10^-31 * 5.934 *10^7/(B*e)

B = 5.151 *10^-4 T

the magnetic field strength is 5.151 *10^-4 T

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