An electron enters a magnetic chamber as depicted below with a velocity of 2.00

Question

An electron enters a magnetic chamber as depicted below with a velocity of 2.00 times 106 m/s. There is a hole a distance of 1.50m from the edge of the chamber. A constant magnetic field (directed into the page) is turned on the moment the electron enters the chamber to direct the electron Into the hole. It is turned off when the appropriate trajectory is achieved. What wwst is the magnitude of the magnetic field required to guide the electron into the hole? How long must the magnetic field be on?

Explanation / Answer

v = 2.00*10^6 m/s, L = 1.50 m, According to the diagram, the electron moves a quarter of circle in the magnetic field. so the radius of the curve r = L = 1.50 m, qvB = mv^2/r so B = mv/(qL) = 7.58*10^-6 T

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