An electrochemical impulse traveling along the cell modeled in the figure (Figur

Question

An electrochemical impulse traveling along the cell modeled in the figure  (Figure 1) changes the value of emf E3 so that now it supplies an upward current of 40 nA . All resistors have the same value R = 4.5 M?and  E1=75mV, E2=45mV.

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Explanation / Answer

Here,

R = 4.5 Mohm

I3 = 40 nA

E1 = 75 mV

E2 = 45 mV

for the value of E3

Using KVL

75 - (4.5 + 4.5) *I1 - E3 + (9)* 40 = 0 -----(1)

Using second KVL equation

45 - 4.5 *I2 - E3 + (9)* 40 = 0 ----(2)

Using KCL

I1 + I2 + 40 = 0 ----(3)

solving 1 2, 3

I1 = -11.11 nA , I2 = -28.9 nA , E3 = 535 mV

the emf E3 is 535 mV

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