A particle with charge 5.00 10-19 C travels in a circular orbit with radius 0.47

Question

A particle with charge 5.00 10-19 C travels in a circular orbit with radius 0.479 m due to the force exerted on it by a magnetic field with magnitude 1.66 T and perpendicular to the orbit. (a) What is the magnitude of the linear momentum p of the particle? kg · m/s (b) What is the magnitude of the angular momentum L of the particle? kg · m2/s A particle with charge 5.00 10-19 C travels in a circular orbit with radius 0.479 m due to the force exerted on it by a magnetic field with magnitude 1.66 T and perpendicular to the orbit. (a) What is the magnitude of the linear momentum p of the particle? kg · m/s (b) What is the magnitude of the angular momentum L of the particle? kg · m2/s A particle with charge 5.00 10-19 C travels in a circular orbit with radius 0.479 m due to the force exerted on it by a magnetic field with magnitude 1.66 T and perpendicular to the orbit. (a) What is the magnitude of the linear momentum p of the particle? kg · m/s (b) What is the magnitude of the angular momentum L of the particle? kg · m2/s

Explanation / Answer

use:
magnetic force = centrepetal acceleration
q*v*B = m*v^2/r
q*B = m*v/r
m*v is momentum
so,
momentum = q*B*r
= (5*10^-19)*1.66*0.479
=3.98*10^-19 Kgm/s

b)
Angular momentum = linear momentum* r
= 3.98*10^-19 *0.479
= 1.9*10^-19 Kgm^2/s

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.