A 22.0-caliber rifle bullet of mass 1.80 g , traveling at 350 m/s , strikes a bl

Question

A 22.0-caliber rifle bullet of mass 1.80 g , traveling at 350 m/s , strikes a block of soft wood, which it penetrates to a depth of 0.140 m . The block of wood is clamped in place and doesn't move. Assume a constant retarding force.

(a)Make a free-body diagram of the bullet while it is slowing down in the wood.

Draw the force vectors with their tails at the dot. The orientation of your vectors will be graded. The exact lengths of your vectors will not be graded but the relative length of one to the other will be graded.

Explanation / Answer

1. its own weight = mg
2. the normal force to the direction opp to its motion in the block as the normal force will oppose it.

since in the horizontal directon only this retarding force is acting as weight is acting downward.

therefore only the retarding force will oppose its motion in the block.
as it is in the direction opp. to that of the motion.


we can use the kinematical eq.

v^2 u^2 = 2as.

v= 0; since finally the bullet will stop
u= 300;
s= 0.140m;
hence find the retardation or the retardind acceleration.

since force experienced on the body is mass x accn.
Hence find the force on the body.

the free body diagram


_________
normal <------- I__________>
|
|
/
mg

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