The force on a wire is a maximum of 6.83 x 10\'2 N when placed between the pole

Question

The force on a wire is a maximum of 6.83 x 10'2 N when placed between the pole faces of a magnet. The current flows horizontally to the right and the magnetic field vertical. The wire is observed to "jump" toward the observer when the current is turned on. What type of magnetic pole is the top pole face? North pole O South pole If the pole faces have a diameter of 13.1 cm, estimate the current in the wire if the field is 0.16 T. A If the wire is tipped so that it makes an angle of 10.0 degree with the horizontal, what force will it now feel?

Explanation / Answer

a) sounth pole

let lamda is the linear charge density of the line of charge.

at a given point,

E = k*lamda*a/( b*(b+a) )

b) magnetic force on a current carrying conductor, F = B*I*L*sin(90)

I = F/(B*L)

= 6.83*10^-2/(0.16*0.131)

= 3.26 A

c) same. 6.83*10^-2 N

here effective length increases.

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