The force acting on a particle varies as in the figure below. (The x axis is mar

Question

The force acting on a particle varies as in the figure below. (The x axis is marked in increments of 1.50 m.)

Find the work done by the force as the particle moves across the following distances.

(a) from x = 0 m to x = 12.0 m

________J

(b) from x = 12.0 m to x = 18.0 m

________J

(c) from x = 0 m to x = 18.0 m

________J

I know that the answers are 36, -9, 25. but what i want to know how to work out the problem, how the answers came to be that way or basically i wanna know how to do this problem step by step... someone please show me.

The force acting on a particle varies as in the figure below. (The x axis is marked in increments of 1.50 m.) Find the work done by the force as the particle moves across the following distances. (a) from x = 0 m to x = 12.0 m ________J (b) from x = 12.0 m to x = 18.0 m ________J (c) from x = 0 m to x = 18.0 m ________J I know that the answers are 36, -9, 25. but what i want to know how to work out the problem, how the answers came to be that way or basically i wanna know how to do this problem step by step... someone please show me.

Explanation / Answer

Work done = Area under the curve ( if curve above x axis then positive , if below x axis then negative )

1) From x = 0 to x = 12

Work done = area of trinagle ABC

= 0.5*base*height

= 0.5*12*6 = 36 J

2) From x = 12 to x = 18

Work done = Area of triangle CDE

= -0.5*base*height

= - 0.5*6*3 = -9 J

2) Work done form x = 0 to x = 18

=  area of trinagle ABC +  area of trinagle CDE

= 36 - 9 = 25 J

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