A 5.9-kg block is pushed 2.9 m up a vertical wall with constant speed by a const

Question

A 5.9-kg block is pushed 2.9 m up a vertical wall with constant speed by a constant force of magnitude F applied at an angle of ? = 30 with the horizontal, as shown in the figure below. If the coefficient of kinetic friction between block and wall is 0.30, determine the following.

b) the work done by the force of gravity

c) the work done by the normal force between block and wall

d) By how much does the gravitational potential energy increase during the block's motion?

A 5.9-kg block is pushed 2.9 m up a vertical wall with constant speed by a constant force of magnitude F applied at an angle of ? = 30½ with the horizontal, as shown in the figure below. If the coefficient of kinetic friction between block and wall is 0.30, determine the following. a) the work done by F rightarrowhead.gif b) the work done by the force of gravity c) the work done by the normal force between block and wall d) By how much does the gravitational potential energy increase during the block's motion?

Explanation / Answer

we need F first

use F sin theta = mg + uN

and N = F cos theta

so   F(sin 30 - 0.3 cos 30) = 5.9 * 9.8

F = 57.82/(0.24002)

F = 240.89 N

so

part A : W = F r sin theta

W = 240.89 * 2.9 * cos 60

W = 349.29 Joule s

-------------------------------

W = Fr cos theta = mgh cos theta

W = 5.9 * 2.9 * 9.8 cos 180

W = 167.67 Joules

--------------------------------

W = Nr cos theta

N = 0 J

as theta = 90 deg
------------------------

U = mgh

U = 5.9*9.8 * 2.9

U = 167.67 Joules

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.