A 4.4 kg toy race car can move along an x axis. The figure below gives F x of th

Question

A 4.4 kg toy race car can move along an x axis. The figure below gives Fx of the force acting on the car, which begins at rest at time t = 0.

A 4.4 kg toy race car can move along an x axis. The figure below gives Fx of the force acting on the car, which begins at rest at time t = 0. v vector = m/s vector p = kg m/s (c) In unit-vector notation, what is the car's velocity at t = 8.0 s? vector p = kg m/s (b) In unit-vector notation, what is the momentum of the car at t = 9.0 s? (a) In unit-vector notation, what is the momentum of the car at t = 2.0 s?

Explanation / Answer

Here ,

Using second law of motion ,

FOrce = change in momentum / time

hence ,

a)

as initially p = 0

then at t = 2 s

P(2) = 0.5 * 25*2

P(2) = 25 i Kg.m/s

the momentum at time t =2 is 25 i kg.m/s

b)

at time t = 9

p(9) = 0.5 * 25*2 + 25*2 + 0.5 * 25*2 - 12.5 * 1 - 12.5 * 1

P(9) = 75i Kg.m/s

the momentum at t =9 s is 75 i Kg.m/s

c)

at t = 8

P(8) =75 + 0.5*12.5 * 1

P(8) = 81.25 Kg.m/s

then

as p =mv

v = 81.25/4.4

v = 18.47 i m/s

the velocity is 18.47 i m/s

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