A 4.1 kg block is attached to a spring with a force constant of 450N/m , as show

Question

A 4.1 kg block is attached to a spring with a force constant of 450N/m , as shown in the figure.

Find the work done by the spring on the block as the block moves from A to B along paths 1 and 2.

Enter your answers numerically separated by commas. Express your answers using two significant figures.

A 4.1 kg block is attached to a spring with a force constant of 450N/m , as shown in the figure. Find the work done by the spring on the block as the block moves from A to B along paths 1 and 2. Enter your answers numerically separated by commas. Express your answers using two significant figures.

Explanation / Answer

Work done by the spring = Spring potential energy at B - Spring potential energy at A

at A , spring is unstretched , so X =0

at A , spring Potential energy =0

At B , spring is streteched by 2 cm , so X = 2 cm = 0.02 m

At B , spring Potential energy = (0.5) k x^2 = (0.5) (450) (0.02)2 = 0.09 J

so work done by the spring = spring potential energy at B - spring potential energy at B

work done by the spring = 0.09 J - 0 J = 0.09 J

for path 2 also , the work done will be same since the work done by spring only depends on initial and final position

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