The area shown is the boundary of a magnetic field directed in the positive z di
ID: 1322719 • Letter: T
Question
The area shown is the boundary of a magnetic field directed in the positive z direction. An electron with a velocity along the x-axis enters the field at coordinates (x, y) = (?5 m, 0) and exits 0.43 ?s later at point A whose coordinates are (x, y) = (0, 5 m).
What is the magnitude of B? ? The mass of the electron is 9.109 10?31 kg and the elemental charge is ?1.602 10?19 C.
Answer in units of microT.
The area shown is the boundary of a magnetic field directed in the positive z direction. An electron with a velocity along the x-axis enters the field at coordinates (x, y) = (?5 m, 0) and exits 0.43 ?s later at point A whose coordinates are (x, y) = (0, 5 m). What is the magnitude of B? ? The mass of the electron is 9.109 ½ 10?31 kg and the elemental charge is ?1.602 10?19 C. Answer in units of microT.Explanation / Answer
charge always constitutes circular motion in presence of magnetic field when it's motion is perpendicular to the direction of megnetic field therefore,
from the information one can say that , radius of the motion of the electron is = 5 m
accrding to theory of cyclotrone
r = (mv) / (q*B)
therefore,
B = (mv) / (qr)
B = (9.1*10^(-31) * v ) / (1.6*10^(-19) * 5)
v = quarter circile ' time taken
v = ( ( 2*pi*5 ) / 4 ) / 0.43 m/s
therefore
B = (9.1*10^(-31) * ( ( ( 2*pi*5 ) / 4 ) / 0.43) ) / (1.6*10^(-19) * 5)
B = 8.9339*10^(-6) micro Tesla
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.