The area shown is the boundary of a magnetic field directed in the positive z di

Question

The area shown is the boundary of a magnetic field directed in the positive z direction. An electron with a velocity along the x-axis enters the field at coordinates (x, y) = (-9 m, 0) and exits 0.57 usec later at point A whose coordinates are (x, y) = (0, 9 m). What is the magnitude of vector B ? The mass of the electron is 9.109 x 10^-31 kg and the elemental charge is ?1.602 10^-19 C. Answer in units of T.

The area shown is the boundary of a magnetic field directed in the positive z direction. An electron with a velocity along the x-axis enters the field at coordinates (x, y) = (-9 m, 0) and exits 0.57 usec later at point A whose coordinates are (x, y) = (0, 9 m). What is the magnitude of vector B ? The mass of the electron is 9.109 x 10^-31 kg and the elemental charge is ?1.602 10^-19 C. Answer in units of T.

Explanation / Answer

Here ,

as in time 0.57 us the electron makes a quater circle

then

Time period , T = 4*.57

T = 2.28 us

Now , as T = 2*pi*m/(B*e)

2.28 *10^-6 = 2*pi*9.109 x 10^-31/(B*1.602

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