A 3.290 kg block of wood rests on a steel desk. The coefficient of static fricti

Question

A 3.290 kg block of wood rests on a steel desk. The coefficient of static friction between the block and the desk is ?s = 0.505 and the coefficient of kinetic friction is ?k = 0.255. At time t = 0, a force F = 10.0 N is applied horizontally to the block. State the force of friction applied to the block by the table at the following times:

Mapoob sapling learning A 3.290 kg block of wood rests on a steel desk. The coefficient of static friction between the block and the desk is = 0.505 and the coefficient of kinetic friction is 0.255. At time t = 0, a force F= 10.0 N is applied horizontally to the block. State the force of friction applied to the block by the table at the following times: t=0 t>0 Number Number 16.3 8.22 Consider the same situation, but this time the external force Fis 20.2 N. Again state the force of friction acting on the block at the following times: t=0 tso Number Number

Explanation / Answer

   f s = F = 10 N

partB)

fmax = us*m*g = 0.505*3.29*9.8 = 16.28221 N

at t > 0 fs = uk*m*g = 8.22171 N

at   t > 0 .....f = fk = uk*m*g

in the second part B the F > fs the body moves

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