A solenoid of cross-sectional area of 0.05 m^2 has 1000 turns per meter. A secon

Question

A solenoid of cross-sectional area of 0.05 m^2 has 1000 turns per meter. A second, single turn of wire is wrapped around the outside of the solenoid, forming a closed loop with a radius of 15 cm. When the current in the solenoid is charging at the rate of 1000 A/s. whats the induced emf in the single, outer loop? ( Hint use Faradau's law of induction)

a) 0.72 V

b) 0.15 V

c) 0.063 V

d) 0.024 V

A solenoid of cross-sectional area of 0.05 m^2 has 1000 turns per meter. A second, single turn of wire is wrapped around the outside of the solenoid, forming a closed loop with a radius of 15 cm. When the current in the solenoid is charging at the rate of 1000 A/s. whats the induced emf in the single, outer loop? ( Hint use Faradau's law of induction) a) 0.72 V b) 0.15 V c) 0.063 V d) 0.024 V

Explanation / Answer

inductance L = uo N^2 A/L

L = 4pi e-7 * 1000*1000*0.05

L = 0.0628 H

now use

induced emf e = L di/dt

emf e = 0.0628 * 1000

emf e = 0.0628 Volts

option C it is

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