A uniform bar has two small balls glued to its ends. The bar is 2.00m long and w

Question

A uniform bar has two small balls glued to its ends. The bar is 2.00m long and with mass 3.30kg , while the balls each have mass 0.300kg and can be treated as point masses.

Part A

Find the moment of inertia of this combination about an axis perpendicular to the bar through its center.

I= kg*m2

Part B

Find the moment of inertia of this combination about an axis perpendicular to the bar through one of the balls.

I= kg*m2

Part C

Find the moment of inertia of this combination about an axis parallel to the bar through both balls.

I= kg*m2

Explanation / Answer

A. I = I of rod + 2 x I of balls

I = 3.30 x 2^2 /12 + 2 x 0.3 x 1^2 = 1.7 kg.m^2

B. I = 3.30 x 2^2 / 3 + 0.3 x 2^2 = 5.6 kg.m^2

C. I = 0

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